FINALTERM EXAMINATION
Fall 2009
CS302- Digital Logic Design (Session - 4)
Ref No:
Time: 120 min
Marks: 75
Student Info | |
StudentID: | |
Center: | |
ExamDate: |
Question No: 1 ( Marks: 1 ) - Please choose one
► FALSE
► TRUE
Question No: 2 ( Marks: 1 ) - Please choose one
I) All the inputs are zero
II) Any of the inputs is zero
III) Any of the inputs is one
IV) All the inputs are one
► I Only
► IV Only
► I and IV only
► II and III only
Question No: 3 ( Marks: 1 ) - Please choose one
► AND Gate and then NOT Gate
► NOT Gate and then AND Gate
► AND Gate and then OR Gate
► OR Gate and then AND Gate
Question No: 4 ( Marks: 1 ) - Please choose one
► Zero
► One
► Undefined
► No output as input is invalid
Question No: 5 ( Marks: 1 ) - Please choose one
► Radiation-Erase programming method (REPM)
► In-System Programming (ISP)
► In-chip Programming (ICP)
► Electronically-Erase programming method(EEPM)
Question No: 6 ( Marks: 1 ) - Please choose one
► !
► &
► #
► $
Question No: 7 ( Marks: 1 ) - Please choose one
► 0
► 1
► Invalid
► Input is invalid
Question No: 8 ( Marks: 1 ) - Please choose one
► Doesn’t have an invalid state
► Sets to clear when both J = 0 and K = 0
► It does not show transition on change in pulse
► It does not accept asynchronous inputs
Question No: 9 ( Marks: 1 ) - Please choose one
► 0
► 1
► Q(t)
► Invalid
Question No: 10 ( Marks: 1 ) - Please choose one
► True
► False
Question No: 11 ( Marks: 1 ) - Please choose one
► Low-to-high transition of clock
► High-to-low transition of clock
► Enable input (EN) is set
► Preset input (PRE) is set
Question No: 12 ( Marks: 1 ) - Please choose one
► J-K input
► S-R input
► D input
► Clear Input (CLR)
Question No: 13 ( Marks: 1 ) - Please choose one
► Asynchronous, synchronous
► Synchronous, asynchronous
► Preset input (PRE), Clear input (CLR)
► Clear input (CLR), Preset input (PRE)
Question No: 14 ( Marks: 1 ) - Please choose one
► AND
► NAND
► NOR
► XNOR
Question No: 15 ( Marks: 1 ) - Please choose one
► Mealy machine
► Moore Machine
► State Reduction table
► State Assignment table
Question No: 16 ( Marks: 1 ) - Please choose one
► State diagram
► Next state table
► State reduction
► State assignment
Question No: 17 ( Marks: 1 ) - Please choose one
► Serial data to parallel
► Parallel data to serial
► Serial data to serial
► Parallel data to parallel
Question No: 18 ( Marks: 1 ) - Please choose one
► It is set to logic low
► It is set to logic high
► Remains in previous state
► State of transmission line is not used to start transmission
Question No: 19 ( Marks: 1 ) - Please choose one
Z PIN 20 ISTYPE ‘reg.invert’;
The keyword “reg.invert” indicates ________
► An inverted register input
► An inverted register input at pin 20
► Active-high Registered Mode output
► Active-low Registered Mode output
Question No: 20 ( Marks: 1 ) - Please choose one
► 2
► 4
► 8
► 16
Question No: 21 ( Marks: 1 ) - Please choose one
► 1
► 0
► A
►
Question No: 22 ( Marks: 1 ) - Please choose one
► 2
► 4
► 6
► 8
Question No: 23 ( Marks: 1 ) - Please choose one
► 1110
► 0111
► 1000
► 1001
Question No: 24 ( Marks: 1 ) - Please choose one
► 1 floating-gate MOS transistor
► 2 floating-gate MOS transistors
► 4 floating-gate MOS transistors
► 6 floating-gate MOS transistors
Question No: 25 ( Marks: 1 ) - Please choose one
► Read Only Memory
► Fist In First Out Memory
► Flash Memory
► Fast Page Access Mode Memory
Question No: 26 ( Marks: 1 ) - Please choose one
► It is locked; no data is allowed to enter
► It is not locked; the new data overwrites the previous data.
► Previous data is swapped out of memory and new data enters
► None of given options
Question No: 27 ( Marks: 1 ) - Please choose one
► Strobing
► Amplification
► Quantization
► Digitization
Question No: 28 ( Marks: 1 ) - Please choose one
Above is the circuit diagram of _______.
► Asynchronous up-counter
► Asynchronous down-counter
► Synchronous up-counter
► Synchronous down-counter
Question No: 29 ( Marks: 1 ) - Please choose one
► Product of sum form
► Sum of product form
► Demorgans law
► Associative law
Question No: 30 ( Marks: 1 ) - Please choose one
The above ABEL expression will be
► Q2:= Q1 $ X $ Q3
► Q2:= Q1 # X # Q3
► Q2:= Q1 & X & Q3
► Q2:= Q1 ! X ! Q3
Question No: 31 ( Marks: 1 )
Question No: 32 ( Marks: 1 )
Question No: 33 ( Marks: 2 )
Ans:
Question No: 34 ( Marks: 2 )
Question No: 35 ( Marks: 3 )
Question No: 37 ( Marks: 3 )
Ans:
Question No: 38 ( Marks: 5 )
Question No: 39 ( Marks: 5 )
Question No: 40 ( Marks: 10 )
Question No: 41 ( Marks: 10 )
Address signals
Data signals
No comments:
Post a Comment
PLEASE COMMENT ABOUT YOUR VISIT AND MY SITE
Note: Only a member of this blog may post a comment.