right is this
Pr[drawing at least 1 ace] = 1 - Pr[drawing 0 aces]
The probability of drawing 0 aces is:
C(48,5)/C(52,5)
reference
http://mathforum.org/library/drmath/view/62620.html
2011/6/14 Muhammad Imran Illyas <imranilyas0786@gmail.com>
Muhammad Imran Ilyas
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Mian Tyre & Rubber Co. Ltd
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