2011/6/14 mc110201112 <mc110201112@vu.edu.pk>
how can it right ? can you prove??????????????
2011/6/14 Ali Iqbal <bc100402427@vu.edu.pk>
where from you have get this dear? it is wrong
right is thisPr[drawing at least 1 ace] = 1 - Pr[drawing 0 aces]
The probability of drawing 0 aces is:
C(48,5)/C(52,5)
reference
http://mathforum.org/library/drmath/view/62620.html--
2011/6/14 Muhammad Imran Illyas <imranilyas0786@gmail.com>
Muhammad Imran Ilyas
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